Physics 1 FROM 3

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Physics 1 FROM 3

Chapter 5 THERMOMETRY AND CALORIMETRY

MAKING A TEMPERATURE SCALE

Q= Rθ-R0R100-R0*100          Where R0 is the resistance at lower fixed point.

Also, Q= Lθ-L0L100-L0*100     Where L0=Lower fixed point or length

     L100=Upper fixed point or length

Example: The resistance of a wire registers 5Ω at lower fixed point and 5.2Ω at upper fixed point. Calculate the temperature when the resistance is 5.5Ω.

Solution

Q= Rθ-R0R100-R0*100 

But R0= 5Ω, R100=5.2Ω, Rθ=5.5Ω

θ=5.5Ω-5Ω5.2Ω-5Ω*100= 0.5Ω0.2Ω*100=250°C

θ = 250°C

par Claude Foumtum
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