Sum of interior angles of a polygon
Sum of interior angles = 180o (n - 2) where n = number of angles
Ex: a) triangle, b) nonagon, c) decagon
Solution:
a) n = 3, sum of interior angles = 180o (3-2) =180o
b) n = 9, sum of interior angles = 180o (9-2) = 1260o
c) n = 10, sum of interior angles = 180o (10-2) = 1440o
